4.9t^2-30t+3=0

Solution for 4.9t^2-30t+3=0 equation:

4.9t^2-30t+3=0

a = 4.9; b = -30; c = +3;
Δ = b2-4ac
Δ = -302-4·4.9·3
Δ = 841.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{841.2}}{2*4.9}=\frac{30-\sqrt{841.2}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{841.2}}{2*4.9}=\frac{30+\sqrt{841.2}}{9.8}
$